[OpenPower-Firmware] SBE questions

[Daniel M Crowell]

Correct.  The way we do it is to make a complete image, and then handle the
ecc/chunking during the write process itself.

--
Dan Crowell
Senior Software Engineer - Power Systems Enablement Firmware
IBM Rochester: t/l 553-2987
dcrowell at us.ibm.com



From:	"Marty E. Plummer" <hanetzer at startmail.com>
To:	Daniel M Crowell <dcrowell at us.ibm.com>
Cc:	Dean Sanner <dsanner at us.ibm.com>,
            openpower-firmware at lists.ozlabs.org, Stewart Smith
            <stewart at linux.ibm.com>
Date:	07/19/2019 04:04 PM
Subject:	[EXTERNAL] Re: [OpenPower-Firmware] SBE questions



On Fri, Jul 19, 2019 at 01:33:14PM -0500, Daniel M Crowell wrote:
>
> I can answer one question.
>
> > Also, why 65529 and not 64*1024=65536?
> With the 9-byte ECC algorithm there are 6 bytes leftover.  We don't cross
> chips with the data/ecc so the last 6 bytes are not part of the image.
>
Ah, so if I were to 'manually' cook an image to write to the seeprom I
would have to be careful about said size? Eg, after adding ecc it cannot
be larger than 4*65529 bytes, and it would need to be split into 3 or 4
65529 byte chunks (maybe not a full 65529 for the last fourth) prior to
writing to the seeprom banks?
> --
> Dan Crowell
> Senior Software Engineer - Power Systems Enablement Firmware
> IBM Rochester: t/l 553-2987
> dcrowell at us.ibm.com



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