[OpenPower-Firmware] SBE questions

[Marty E. Plummer]

On Fri, Jul 19, 2019 at 01:33:14PM -0500, Daniel M Crowell wrote:
> 
> I can answer one question.
> 
> > Also, why 65529 and not 64*1024=65536?
> With the 9-byte ECC algorithm there are 6 bytes leftover.  We don't cross
> chips with the data/ecc so the last 6 bytes are not part of the image.
> 
Ah, so if I were to 'manually' cook an image to write to the seeprom I
would have to be careful about said size? Eg, after adding ecc it cannot
be larger than 4*65529 bytes, and it would need to be split into 3 or 4
65529 byte chunks (maybe not a full 65529 for the last fourth) prior to
writing to the seeprom banks?
> --
> Dan Crowell
> Senior Software Engineer - Power Systems Enablement Firmware
> IBM Rochester: t/l 553-2987
> dcrowell at us.ibm.com