How to boot powerPC linux-2.6.10 from diifferent address other than 0x0000
yang.reeve at gmail.com
Tue Aug 29 09:37:18 EST 2006
You need to do two things:
- mem remap your boot sector memory block to virtual address 0xc0008000
- using uboot commond "go xxx" to boot it from 0xc0008000, or define env
variable "bootcmd", and run "boot".
On 8/25/06, Reddy Suneel-ASR125 <suneel.reddy at motorola.com> wrote:
> We are working on MPC 8540, Linux kernel version is 2.6.10 from
> Montavista. The bootloader used in Uboot and currently it loads the uImage
> at physical memory address 0x0 and transfers control to it. We want to load
> the kernel at a different address say 0x8000 and for this we made the
> following changes.
> 1) Altered the Makefile to linked the kernel at virtual address 0xc0008000
> ( the default was 0xc000:0000)
> 2) Modified Uboot to load kernel at 0x8000 instead of 0x0
> The kernel space still starts from 0xc000:0000
> When we transferred control to the kernel (loaded at 0x8000) we found that
> the execution proceeds only till the mapping and invalidation on TLBs. We do
> not know where the control goes after this as the further instructions does
> not seems to get executed. Currently we do not have the provision to connect
> a debugger and hence we are unable to make out what is happening.
> Can some one give us any clue as to what we might have done wrong? This is
> our first experience on PowerPC.
> Linuxppc-embedded mailing list
> Linuxppc-embedded at ozlabs.org
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