[phosphor-sel-logger] How to add a journal entry manually

[Bills, Jason M]

On 10/25/2021 5:02 AM, Chris Chen (TPI) wrote:
> Hi all,
> 
> I for now have added rsyslog and phosphor-sel-logger packages to build 
> the image, then I could see the xyz.openbmc_project.Logging.IPMI through 
> the busctl command after the system runs up.
> 
>  From this link, 
> https://lists.ozlabs.org/pipermail/openbmc/2019-October/018640.html 
> <https://lists.ozlabs.org/pipermail/openbmc/2019-October/018640.html>, I 
> understand that I should be able to add a journal entry that has the 
> IPMI SEL MESSAGE_ID: "b370836ccf2f4850ac5bee185b77893a" to test the 
> feature, but I don't know to give the correct parameters to the method 
> call, IpmiSelAdd, as below,
> 
> ~# busctl call xyz.openbmc_project.Logging.IPMI 
> /xyz/openbmc_project/Logging/IPMI xyz.openbmc_project.Logging.IPMI 
> IpmiSelAdd xxx
> 
> Could someone help me out on this? Thank you.
You can find the implementation for IpmiSelAdd, here: 
https://github.com/openbmc/phosphor-sel-logger/blob/master/src/sel_logger.cpp#L270.

"IpmiSelAdd", [](const std::string& message, const std::string& path,
                     const std::vector<uint8_t>& selData,
                     const bool& assert, const uint16_t& genId)

Where
message = the string to set as the MESSAGE in the journal
path = the D-Bus path to the sensor that logged the event
selData = the raw bytes of the IPMI SEL entry
assert = the event direction of the SEL event
genId = the Generator ID for the SEL event

The busctl format is 'ssaybq', so a sample command is
busctl call xyz.openbmc_project.Logging.IPMI 
/xyz/openbmc_project/Logging/IPMI xyz.openbmc_project.Logging.IPMI 
IpmiSelAdd ssaybq "helloworld" "/xyz/openbmc_project/Test" 3 16 32 64 
true 0x81

This should add an IPMI message to the journal that is picked up by 
rsyslog and sent to /var/log/ipmi_sel like this:

root at intel-obmc:~# cat /var/log/ipmi_sel
2021-08-20T01:16:48.747428+00:00 1,2,102040,81,/xyz/openbmc_project/Test,1


> 
> Regards,
> 
> Chris Chen.
> 
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