[PATCH v3 13/26] x86/numa_emu: simplify allocation of phys_dist

[Mike Rapoport]

From: "Mike Rapoport (Microsoft)" <rppt at kernel.org>

By the time numa_emulation() is called, all physical memory is already
mapped in the direct map and there is no need to define limits for
memblock allocation.

Replace memblock_phys_alloc_range() with memblock_alloc().

Signed-off-by: Mike Rapoport (Microsoft) <rppt at kernel.org>
Reviewed-by: Jonathan Cameron <Jonathan.Cameron at huawei.com>
Tested-by: Zi Yan <ziy at nvidia.com> # for x86_64 and arm64
---
 arch/x86/mm/numa_emulation.c | 8 ++------
 1 file changed, 2 insertions(+), 6 deletions(-)

diff --git a/arch/x86/mm/numa_emulation.c b/arch/x86/mm/numa_emulation.c
index 1ce22e315b80..439804e21962 100644
--- a/arch/x86/mm/numa_emulation.c
+++ b/arch/x86/mm/numa_emulation.c
@@ -448,15 +448,11 @@ void __init numa_emulation(struct numa_meminfo *numa_meminfo, int numa_dist_cnt)
 
 	/* copy the physical distance table */
 	if (numa_dist_cnt) {
-		u64 phys;
-
-		phys = memblock_phys_alloc_range(phys_size, PAGE_SIZE, 0,
-						 PFN_PHYS(max_pfn_mapped));
-		if (!phys) {
+		phys_dist = memblock_alloc(phys_size, PAGE_SIZE);
+		if (!phys_dist) {
 			pr_warn("NUMA: Warning: can't allocate copy of distance table, disabling emulation\n");
 			goto no_emu;
 		}
-		phys_dist = __va(phys);
 
 		for (i = 0; i < numa_dist_cnt; i++)
 			for (j = 0; j < numa_dist_cnt; j++)
-- 
2.43.0