[PATCH] powerpc: Fix a wrong version calculation issue in ld_version

Ojaswin Mujoo ojaswin at linux.ibm.com
Tue Jan 3 20:57:40 AEDT 2023


** The Issue **

The ld_version() function seems to compute the wrong version value for
certain ld versions like the following:

$ ld --version GNU ld (GNU Binutils; SUSE Linux Enterprise 15)
2.37.20211103-150100.7.37

For input 2.37.20211103, the value computed is 202348030000 which is way
more the value for a higher version like 2.39.0, that is 23900000.

This issue was highlighted because with the above ld version, my powerpc
kernel build started failing with ld error: "unrecognized option
--no-warn-rwx-segments".  This was caused due to the recent patch
579aee9fc594 added --no-warn-rwx-segments linker flag if the ld version
was greater than 2.39.

Due to the bug in ld_version(), my ld version (2.37.20111103) was
wrongly calculated to be greater than 2.39 and the unsupported flag was
added.

** The fix **

If version is of the form x.y.z and length(z) == 8, then most probably
it is a date [yyyymmdd]. As an approximation, discard the dd and yyyy
parts and keep the mm part in the version.

Signed-off-by: Ojaswin Mujoo <ojaswin at linux.ibm.com>
---

This is just an approximation since I'm not sure how common such release
versions for ld are and I didn't wan't to uneccassarily complicate the
logic. In case we want more accuracy we can try to use the last 4/5
digits to represent a more accurate date.  Let me know if that would be
the preferred way.

PS: This issue also exists in ./scripts/ld-version.sh and I can look
into fixing that after this patch.

 arch/powerpc/boot/wrapper | 4 ++++
 1 file changed, 4 insertions(+)

diff --git a/arch/powerpc/boot/wrapper b/arch/powerpc/boot/wrapper
index af04cea82b94..af2688f79224 100755
--- a/arch/powerpc/boot/wrapper
+++ b/arch/powerpc/boot/wrapper
@@ -210,6 +210,10 @@ ld_version()
 	gsub(".*version ", "");
 	gsub("-.*", "");
 	split($1,a, ".");
+	if( length(a[3]) == "8" )
+		# a[3] is probably a date of format yyyymmdd. An 8 digit number will break
+		# the function so just keep the "mm" part as an approximation
+		a[3] = substr(a[3],5,2);
 	print a[1]*100000000 + a[2]*1000000 + a[3]*10000;
 	exit
     }'
-- 
2.31.1



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