[PATCH v4 05/25] reboot: Warn if restart handler has duplicated priority

Rafael J. Wysocki rafael at kernel.org
Sat Dec 11 05:27:55 AEDT 2021


On Mon, Nov 29, 2021 at 12:34 PM Dmitry Osipenko <digetx at gmail.com> wrote:
>
> 29.11.2021 03:26, Michał Mirosław пишет:
> > On Mon, Nov 29, 2021 at 12:06:19AM +0300, Dmitry Osipenko wrote:
> >> 28.11.2021 03:28, Michał Mirosław пишет:
> >>> On Fri, Nov 26, 2021 at 09:00:41PM +0300, Dmitry Osipenko wrote:
> >>>> Add sanity check which ensures that there are no two restart handlers
> >>>> registered with the same priority. Normally it's a direct sign of a
> >>>> problem if two handlers use the same priority.
> >>>
> >>> The patch doesn't ensure the property that there are no duplicated-priority
> >>> entries on the chain.
> >>
> >> It's not the exact point of this patch.
> >>
> >>> I'd rather see a atomic_notifier_chain_register_unique() that returns
> >>> -EBUSY or something istead of adding an entry with duplicate priority.
> >>> That way it would need only one list traversal unless you want to
> >>> register the duplicate anyway (then you would call the older
> >>> atomic_notifier_chain_register() after reporting the error).
> >>
> >> The point of this patch is to warn developers about the problem that
> >> needs to be fixed. We already have such troubling drivers in mainline.
> >>
> >> It's not critical to register different handlers with a duplicated
> >> priorities, but such cases really need to be corrected. We shouldn't
> >> break users' machines during transition to the new API, meanwhile
> >> developers should take action of fixing theirs drivers.
> >>
> >>> (Or you could return > 0 when a duplicate is registered in
> >>> atomic_notifier_chain_register() if the callers are prepared
> >>> for that. I don't really like this way, though.)
> >>
> >> I had a similar thought at some point before and decided that I'm not in
> >> favor of this approach. It's nicer to have a dedicated function that
> >> verifies the uniqueness, IMO.
> >
> > I don't like the part that it traverses the list second time to check
> > the uniqueness. But actually you could avoid that if
> > notifier_chain_register() would always add equal-priority entries in
> > reverse order:
> >
> >  static int notifier_chain_register(struct notifier_block **nl,
> >               struct notifier_block *n)
> >  {
> >       while ((*nl) != NULL) {
> >               if (unlikely((*nl) == n)) {
> >                       WARN(1, "double register detected");
> >                       return 0;
> >               }
> > -             if (n->priority > (*nl)->priority)
> > +             if (n->priority >= (*nl)->priority)
> >                       break;
> >               nl = &((*nl)->next);
> >       }
> >       n->next = *nl;
> >       rcu_assign_pointer(*nl, n);
> >       return 0;
> >  }
> >
> > Then the check for uniqueness after adding would be:
> >
> >  WARN(nb->next && nb->priority == nb->next->priority);
>
> We can't just change the registration order because invocation order of
> the call chain depends on the registration order

It doesn't if unique priorities are required and isn't that what you want?

> and some of current
> users may rely on that order. I'm pretty sure that changing the order
> will have unfortunate consequences.

Well, the WARN() doesn't help much then.

Either you can make all of the users register with unique priorities,
and then you can make the registration reject non-unique ones, or you
cannot assume them to be unique.


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