[RFC PATCH 12/29] memblock: replace alloc_bootmem_low with memblock_alloc_low

[Mike Rapoport]

The alloc_bootmem_low(size) allocates low memory with default alignement
and can be replcaed by memblock_alloc_low(size, 0)

Signed-off-by: Mike Rapoport <rppt at linux.vnet.ibm.com>
---
 arch/arm64/kernel/setup.c     | 2 +-
 arch/unicore32/kernel/setup.c | 2 +-
 2 files changed, 2 insertions(+), 2 deletions(-)

diff --git a/arch/arm64/kernel/setup.c b/arch/arm64/kernel/setup.c
index 5b4fac4..cf7a7b7 100644
--- a/arch/arm64/kernel/setup.c
+++ b/arch/arm64/kernel/setup.c
@@ -213,7 +213,7 @@ static void __init request_standard_resources(void)
 	kernel_data.end     = __pa_symbol(_end - 1);
 
 	for_each_memblock(memory, region) {
-		res = alloc_bootmem_low(sizeof(*res));
+		res = memblock_alloc_low(sizeof(*res), 0);
 		if (memblock_is_nomap(region)) {
 			res->name  = "reserved";
 			res->flags = IORESOURCE_MEM;
diff --git a/arch/unicore32/kernel/setup.c b/arch/unicore32/kernel/setup.c
index c2bffa5..9f163f9 100644
--- a/arch/unicore32/kernel/setup.c
+++ b/arch/unicore32/kernel/setup.c
@@ -207,7 +207,7 @@ request_standard_resources(struct meminfo *mi)
 		if (mi->bank[i].size == 0)
 			continue;
 
-		res = alloc_bootmem_low(sizeof(*res));
+		res = memblock_alloc_low(sizeof(*res), 0);
 		res->name  = "System RAM";
 		res->start = mi->bank[i].start;
 		res->end   = mi->bank[i].start + mi->bank[i].size - 1;
-- 
2.7.4