RFC on writel and writel_relaxed
okaya at codeaurora.org
Thu Mar 22 02:04:19 AEDT 2018
On 3/21/2018 9:35 AM, David Laight wrote:
>> x86 has compiler barrier inside the relaxed() API so that code does not
>> get reordered. ARM64 architecturally guarantees device writes to be observed
>> in order.
> There are places where you don't even need a compile barrier between
> every write.
> I had horrid problems getting some ppc code (for a specific embedded SoC)
> optimised to have no extra barriers.
> I ended up just writing through 'pointer to volatile' and adding an
> explicit 'eieio' between the block of writes and status read.
> No less painful was doing a byteswapping write to normal memory.
If the architecture is reordering writes to the peripheral, then removing
the compiler barrier can break the multi-arch drivers. barriers document
clearly states that device need to observe writes in order.
Though for special cases like you mentioned, you can certainly do this:
/* flush everything */
There would be no ordering guarantee between the wmb() and mmiowb().
This can only be done for known code and known hardware. I don't believe
this applies to multi-arch drivers.
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