Can't write value into memory ?(E500 V2)
Scott Wood
scottwood at freescale.com
Thu Aug 27 05:20:31 EST 2009
On Wed, Aug 26, 2009 at 10:39:24PM +0800, wilbur.chan wrote:
> In an assemblely code , I invalided all the TLB entries except for
> the entry we are executed in.
>
> After that , I setuped a 1:1 TLB entry mapping of 1GB .
What is it you're trying to do?
> At last , I wrote value 30 into the physical address 0x0400,0000 (also
> the virtual address because of my 1:1 mapping).
>
> However, it seemed failed to store the value '30' at address
> 0x400,0000. The following is my code:
>
> //code start
>
> // setup a 1:1 mapping of 1GB
> ...
"..." is not code. :-)
> //store '30' into address 0x0400,0000
>
> li r23, 30
> lis r22, 0x400
> ori r22,r22,0x0
> stb r23,0(r22)
>
>
> //check if we successfully store value at 0x400,0000
>
> lis r22, 0x400
> ori r22,r22,0x0
> lwz r23,0(r22)
> cmpw r23, 30
The values should not be equal, since you wrote a byte and read back a
word.
Furthermore, you are storing the constant 30, but are comparing r23 with
the register r30 (I never liked that aspect of ppc asm syntax -- too
error prone). If you want to compare with the constant 30, use "cmpwi".
> beq print_equal
>
> 1: b 1b
>
> print_equal:
> ...
> //code end
>
> I found that, print_equal was not called ,the whole code seemed to
> enter an infinite loop.
That's because you have an infinite loop in your code, right after "beq
print_equal".
-Scott
More information about the Linuxppc-dev
mailing list