DTC memory reserve question

[Benjamin Herrenschmidt]

On Mon, 2005-07-18 at 15:25 -0500, Jon Loeliger wrote:
> So, when the Device Tree Compiler lays down a memory
> reserve table into an assembly file, it always adds
> a reserved region covering the whole DT blob itself.
> That is, it does this:
> 
>         .balign 8
>         .globl  dt_reserve_map
> dt_reserve_map:
> _dt_reserve_map:
>         .long   0, _dt_blob_start
>         .long   0, _dt_blob_end - _dt_blob_start
>         .llong  0
>         .llong  0
> 
> Naturally, that yields System.map entries like this:
> 
> c0013988 t _dt_blob_start
> c0013988 T dt_blob_start
> c0013988 t _dt_header
> c0013988 T dt_header
> c00139b0 t _dt_reserve_map
> c00139b0 T dt_reserve_map
> c00139d0 t _dt_struct_start
> c00139d0 T dt_struct_start
> c0013df0 t _dt_strings_start
> c0013df0 T dt_strings_start
> c0013df0 t _dt_struct_end
> c0013df0 T dt_struct_end
> c0013f05 t _dt_blob_end
> c0013f05 T dt_blob_end
> 
> Notice that these are 0xC-gazillion addresses.

How are you getting these addresses ? You are trying to link the output
of dtc with the kernel directly ? Hrm...  That will not work for that
(and maybe a couple of other things). Might be better to link it with
the zImage wrapper...

Ben.