[Cbe-oss-dev] [RFC, PATCH] CELL Oprofile SPU profiling updated patch
Carl Love
cel at us.ibm.com
Sat Feb 10 08:52:45 EST 2007
On Fri, 2007-02-09 at 13:36 -0600, Milton Miller wrote:
> On Feb 9, 2007, at 11:42 AM, Carl Love wrote:
>
> > On Thu, 2007-02-08 at 09:48 -0600, Milton Miller wrote:
> >> This is part 2, with specific comments to the existing patch.
> >> I'm not subscribed to the list, so please cc.
> >>
> >> Thanks,
> >> milton
> >>
> >> miltonm at bga.com Milton Miller
>
> >>
> >> so samples[spu][entry] = spu_pc_lower;
> >> samples[spu + SPUS_PER_ENTRY][entry] = spu_pc_upper
> >>
> >> hmm... upper and lower seem to be confused here ... the
> >> data is naturarly big endian at the source, so upper should
> >> be 0 and lower 1 .... or just make that spu_pc[2], use 0
> >> and 1 ... yes, a for (j = 0; j < WORDS_PER_ENTRY] loop
> >> assingnig to samples[spu + j * spus_per_word][entry] --- the
> >> compiler should unrol a fixed count of 2.
>
>
> >
> > I think you missed the layout here. This has nothing to do with big or
> > little endian.
>
> Actually, I think I have it exactly right, but are missing
> my point. If you consider 0 to be the first, and 7 to be
> the last spu, then the order of the SPUs in the trace array
> is big endian. I was referring to the order of the elemnts
> in the two words.
>
>
> > The trace buffer is a 128 bit wide, 1024 entry hardware
> > buffer. It takes two 64 bit reads to get the entire 128 bits. Hence,
> > one read gives you the lower 64 bits of the trace buffer. The other
> > read gives you the upper 64 bits of the trace buffer. The SPU PC are
> > 18
> > bits wide but the lower 2 bits are always zero. Only the upper 16 bits
> > of the 18 bit PC are stored in the trace buffer. The hardware stores
> > the eight 16 bit PC values into the 128 bit entry. The spu_pc_lower
> > variable holds the program counter for the lower 4 SPUs 0 to 3.. The
> > spu_pc_upper holds the program counters for the upper 4 SPUS, 4 to 7.
> >
> > In IBM notation the MSB of a word is bit 0, the LSB is n-1 where n is
> > the size of the word.
> >
> > The cbe_read_trace_buffer() function puts trace buffer bits 0:63 into
> > trace[0] and bits 64:127 into trace[1]. So the trace[0] is: bits 0:15
> > is SPU PC 0, 16:31 is SPU PC 1, 32:47 is SPU PC 2 and bits 48:63 is SPU
> > PC 3. The layout of the trace[1] variable is the same except it has
> > SPU
> > PC 4 through 7.
>
> Yes, and trace[0] would be considered the most significant part of the
> trace word, which would normally be called the upper word. If think
> of the spu number as big endian it makes sense. If you think of it
> as little endian, then you have this upper vs lower conflict.
>
OK, it sounds like when you see the variable name spu_pc_lower and
spu_pc_upper in the above context you are thinking of the trace buffer
words. That was not the intention of the variable names. The
lower/upper in the name refers to the range of spu numbers 0-3/4-7.
There was no intention of it having anything to do with the word order
or how the numbers mapped to the trace[0], trace[1] words. If it did I
would have named the variable something like upper_word and lower_word.
So, given that the context and the use of upper and lower in the
variable names seems to be the issue, I need to change the code to
remove the names and use different names that will not contain the upper
and lower terms. Do you agree?
Carl Love
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